Добавить
Уведомления

A differential function `y=f(x)` satisfies `f"(x)-(f(x))^2+5` and `f(0)=1`. Then the equation o...

To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW A differential function `y=f(x)` satisfies `f"(x)-(f(x))^2+5` and `f(0)=1`. Then the equation of tangent at the point where the curve crosses y-axis is

12+
13 просмотров
год назад
12+
13 просмотров
год назад

To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW A differential function `y=f(x)` satisfies `f"(x)-(f(x))^2+5` and `f(0)=1`. Then the equation of tangent at the point where the curve crosses y-axis is

, чтобы оставлять комментарии